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efi_selftest: on sandbox use host specific assembly

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The selftest checking the handling of exceptions in UEFI binaries is using
assembly to provide an undefined instruction. On the sandbox the correct
form of the instruction depends on the host architecture.

Signed-off-by: Heinrich Schuchardt <heinrich.schuchardt@canonical.com>
Reviewed-by: Ilias Apalodimas <ilias.apalodimas@linaro.org>
This commit is contained in:
Heinrich Schuchardt
2022-09-02 02:46:37 +02:00
parent e053a144ca
commit 2b7a6e013f
1 changed files with 9 additions and 2 deletions
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11
lib/efi_selftest/efi_selftest_miniapp_exception.c
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@@ -9,6 +9,7 @@
#include <common.h>
#include <efi_api.h>
#include <host_arch.h>
/*
* Entry point of the EFI application.
@@ -33,10 +34,16 @@ efi_status_t EFIAPI efi_main(efi_handle_t handle,
asm volatile (".word 0xe7f7defb\n");
#elif defined(CONFIG_RISCV)
asm volatile (".word 0xffffffff\n");
#elif defined(CONFIG_SANDBOX)
asm volatile (".word 0xffffffff\n");
#elif defined(CONFIG_X86)
asm volatile (".word 0xffff\n");
#elif defined(CONFIG_SANDBOX)
#if (HOST_ARCH == HOST_ARCH_ARM || HOST_ARCH == HOST_ARCH_AARCH64)
asm volatile (".word 0xe7f7defb\n");
#elif (HOST_ARCH == HOST_ARCH_RISCV32 || HOST_ARCH == HOST_ARCH_RISCV64)
asm volatile (".word 0xffffffff\n");
#elif (HOST_ARCH == HOST_ARCH_X86 || HOST_ARCH == HOST_ARCH_X86_64)
asm volatile (".word 0xffff\n");
#endif
#endif
con_out->output_string(con_out, u"Exception not triggered.\n");
return EFI_ABORTED;