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webp_quality should return '0' in case of success.
-> clarify the return value in case of error Change-Id: I6f1e675c80d237b302fada28e7612a684b931c7a
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@ -18,23 +18,25 @@
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int main(int argc, const char *argv[]) {
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int c;
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int quiet = 0;
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for (c = 1; c < argc; ++c) {
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int ok = 1;
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for (c = 1; ok && c < argc; ++c) {
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if (!strcmp(argv[c], "-quiet")) {
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quiet = 1;
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} else if (!strcmp(argv[c], "-help") || !strcmp(argv[c], "-h")) {
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printf("webp_quality [-h][-quiet] webp_files...\n");
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return 1;
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return 0;
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} else {
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const char* const filename = argv[c];
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const uint8_t* data = NULL;
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size_t data_size = 0;
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int q;
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const int ok = ImgIoUtilReadFile(filename, &data, &data_size);
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if (!ok) continue;
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ok = ImgIoUtilReadFile(filename, &data, &data_size);
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if (!ok) break;
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q = VP8EstimateQuality(data, data_size);
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if (!quiet) printf("[%s] ", filename);
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if (q < 0) {
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fprintf(stderr, "Not a WebP file, or not a lossy WebP file.\n");
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ok = 0;
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} else {
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if (!quiet) {
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printf("Estimated quality factor: %d\n", q);
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@ -45,5 +47,5 @@ int main(int argc, const char *argv[]) {
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free((void*)data);
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}
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}
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return 1;
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return ok ? 0 : 1;
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}
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