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Makefile: Suppress output of python libfdt build command
This should not be printed by default. Prefix it with $(Q).
Fixes ee95d10b
: ("fdt: Build the new python libfdt module")
Signed-off-by: Bin Meng <bmeng.cn@gmail.com>
This commit is contained in:
@@ -131,8 +131,8 @@ fit_check_sign-objs := $(dumpimage-mkimage-objs) fit_check_sign.o
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# all three files in $(obj)/tools: _libfdt.so, libfdt.py and libfdt_wrap.c
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# all three files in $(obj)/tools: _libfdt.so, libfdt.py and libfdt_wrap.c
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# The latter is a temporary file which we could actually remove.
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# The latter is a temporary file which we could actually remove.
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tools/_libfdt.so: $(LIBFDT_SRCS) $(LIBFDT_SWIG)
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tools/_libfdt.so: $(LIBFDT_SRCS) $(LIBFDT_SWIG)
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cp $(LIBFDT_SWIG) tools/.
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$(Q)cp $(LIBFDT_SWIG) tools/.
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unset CC; \
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$(Q)unset CC; \
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unset CROSS_COMPILE; \
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unset CROSS_COMPILE; \
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LDFLAGS="$(HOSTLDFLAGS)" CFLAGS= VERSION="u-boot-$(UBOOTVERSION)" \
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LDFLAGS="$(HOSTLDFLAGS)" CFLAGS= VERSION="u-boot-$(UBOOTVERSION)" \
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CPPFLAGS="$(_hostc_flags)" OBJDIR=tools \
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CPPFLAGS="$(_hostc_flags)" OBJDIR=tools \
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